$\frac{\-3(3^2-3)}{\1-7}$
You asked:
Evaluate the expression: \(\frac{-\left( 3 \left({3}^{2} - 3\right) \right)}{1 - 7}\)
MathBot Answer:
\[\frac{-\left( 3 \left({3}^{2} - 3\right) \right)}{1 - 7} = 3\]
\[\begin{aligned}\frac{-\left( 3 \left({3}^{2} - 3\right) \right)}{1 - 7}& = - \cdot 3 \cdot \left(3^{2} - 3\right) \cdot \frac{1}{1 - 7}\\& = - \cdot 3 \cdot \left(9 - 3\right) \cdot \frac{1}{1 - 7}\\& = - \cdot 3 \cdot 6 \cdot \frac{1}{1 - 7}\\& = - \cdot 18 \cdot \frac{1}{1 - 7}\\& = - \cdot \frac{18}{-6}\\& = - -3\\& = 3\end{aligned}\]