2^x×8^x-1÷16^x-1

asked by guest
on Jan 24, 2025 at 12:22 pm



You asked:

Evaluate the expression: \({2}^{x} \cdot {8}^{x} - \frac{1}{{16}^{x}} - 1\)

MathBot Answer:

Evaluated



\(\displaystyle {2}^{x} \cdot {8}^{x} - \frac{1}{{16}^{x}} - 1 = 16^{x} - 1 - 16^{- x} \)

Factored

\[{2}^{x} \cdot {8}^{x} - \frac{1}{{16}^{x}} - 1 = 16^{- x} \left(16^{2 x} - 16^{x} - 1\right)\]

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