P(x≥40)=
i=40
∑
N
(
i
N
)⋅p
i
⋅(1−p)
N−i
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
P(x≥40)=
i=40
∑
N
(
i
N
)⋅p
i
⋅(1−p)
N−i
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.