x³ + 1 <= 2x

asked by guest
on Mar 27, 2025 at 9:31 am



You asked:

Solve the inequality x3+1≤2x {x}^{3} + 1 \le 2 x for the variable xx.

MathBot Answer:

x≤−52−12∧−12+52≤x≤1x \leq - \frac{\sqrt{5}}{2} - \frac{1}{2} \wedge - \frac{1}{2} + \frac{\sqrt{5}}{2} \le x\leq1

+ Submit Question