($8/6)^{2x-1}$ = $(25/4)^{2x}$
You asked:
Solve the equation \({\left( \frac{8}{6} \right)}^{2 x - 1} = {\left( \frac{25}{4} \right)}^{2 x}\) for the variable \(x\).
MathBot Answer:
The solution is: \[x = \frac{- \log{\left(3 \right)} + 2 \log{\left(2 \right)}}{2 \left(- \log{\left(75 \right)} + 4 \log{\left(2 \right)}\right)} \approx -0.093107057\]