$4.9x^{2}$ + 13x -7 = 0 find the roots
You asked:
Find the zeros of \(4.9 \cdot {x}^{2} + 13 x - 7 = 0\)
MathBot Answer:
The zeros of \(x^{2} \cdot \left(9 \cdot \frac{1}{10} + 4\right) + 13 x - 7 = 0\) are: $$\begin{align*}x &= - \frac{65}{49} + \frac{\sqrt{7655}}{49} \approx 0.459037894924248\\x &= - \frac{\sqrt{7655}}{49} - \frac{65}{49} \approx -3.11209911941404\end{align*}$$