solve using factorisation:
(x+3)(x-8)+10=0
MathBot Answer:
$$\begin{aligned}0 &= \left(x + 3\right) \left(x - 8\right) + 10\\&= \left(x - 7\right) \left(x + 2\right)\end{aligned}$$$$x \in \left\{-2, 7\right\}$$
asked 12 days ago
active 12 days ago