πΆππ 2π₯ β 10Β° β πππ(π₯ + 30Β°) = 1
You asked:
Solve the equation \(\cos\left( 2 x \right) - 10^{\circ} \cdot \sec\left( x + 30^{\circ} \right) = 1\) for the variable \(x\).
πΆππ 2π₯ β 10Β° β πππ(π₯ + 30Β°) = 1
You asked: