32cos^6 theta = cos 6theta + 6cos 4theta + 15cos 2theta + 10

asked by guest
on Nov 14, 2024 at 2:02 am



You asked:

Solve the equation 32cos⁡(θ)6=cos⁡(6θ)+6cos⁡(4θ)+15cos⁡(2θ)+1032 {\cos\left( θ \right)}^{6} = \cos\left( 6 θ \right) + 6 \cos\left( 4 θ \right) + 15 \cos\left( 2 θ \right) + 10 for the variable θθ.

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