32cos^6 theta = cos 6theta + 6cos 4theta + 15cos 2theta + 10

asked by guest
on Nov 14, 2024 at 2:02 am



You asked:

Solve the equation \(32 \cdot {\cos\left( θ \right)}^{6} = \cos\left( 6 θ \right) + 6 \cdot \cos\left( 4 θ \right) + 15 \cdot \cos\left( 2 θ \right) + 10\) for the variable \(θ\).

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