a(n) = -\dfrac{1}{16} \left(2\right)^{n - 1}

asked by guest
on Oct 18, 2024 at 7:21 am



You asked:

Investigate the relation \(a\left( n \right) = -\left( \frac{1}{16} \cdot {2}^{n - 1} \right)\).

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