find the equation of a line with a gradient of 3 and a y intercept of 2

asked by guest
on Mar 23, 2025 at 11:52 am



You asked:

Find an equation of the line with slope 33 and y-intercept (0,2)(0, 2).

MathBot Answer:

Standard Form:

Ax+By+C=0\begin{aligned}Ax + By + C = 0\end{aligned}Slope=ABAB=31A=3,B=1\begin{aligned} \text{Slope} &= -\frac{A}{B} \\ -\frac{A}{B} &= \frac{3}{1} \\ A =& -3, B = 1 \end{aligned}3x+1y+C=03(0)+1(2)+C=00+2+C=02+C=0C=2\begin{aligned}-3 x + 1 y + C &= 0 \\ -3(0) + 1(2) + C &= 0 \\ 0 + 2 + C &= 0 \\ 2 + C &= 0 \\ C &= -2 \end{aligned}An equation of the line in standard form is: 3x+y2=0- 3 x + y - 2 = 0.


Slope-Intercept Form:

y=mx+b\begin{aligned} y = mx+b\end{aligned}y=3x+b2=3×0+b2=0+bb=2\begin{aligned}y &= 3x + b \\ 2 &= 3 \times 0 + b \\ 2 &= 0 + b \\ b &= 2 \end{aligned}The slope-intercept form of the line is: y=3x+2y = 3 x + 2.