Math Problem Solver

\[ 2\frac{3}{4} + 1\frac{1}{2} - \frac{1}{3} = \frac{47}{12} = 3.91\overline{6} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{2}{1}\), \(\frac{3}{4}\), \(\frac{1}{1}\), \(\frac{1}{2}\), and \(\frac{-1}{3}\) is \(12\). \[ \begin{aligned} 2\frac{3}{4} + 1\frac{1}{2} - \frac{1}{3} &= \frac{2 \cdot 12}{1 \cdot 12} + \frac{3 \cdot 3}{4 \cdot 3} + \frac{1 \cdot 12}{1 \cdot 12} + \frac{1 \cdot 6}{2 \cdot 6} + \frac{-1 \cdot 4}{3 \cdot 4} \\ &= \frac{24 + 9 + 12 + 6 + -4}{12} \\ &= \frac{47}{12} \end{aligned} \]