6x-5y+27=0

asked by guest
on Nov 24, 2024 at 12:42 am



You asked:

Investigate the equation: \(6 x - 5 y + 27 = 0\).

MathBot Answer:

The graph of \(6 x - 5 y + 27 = 0\) is a line.

The x-intercept is \(- \frac{9}{2}\).

The y-intercept is \(\frac{27}{5}\).

The slope of the line is \(\frac{6}{5}\).

The slope-intercept form of the line is \(y = \frac{6 x}{5} + \frac{27}{5}\).

The line in standard form is \( 6 x - 5 y + 27 = 0 \)