express 1 over x+3 + 3 over x^2-9
You asked:
Evaluate the expression: \(\frac{1}{x} + 3 + \frac{3}{{x}^{2}} - 9\)
MathBot Answer:
Evaluated
\(\displaystyle \frac{1}{x} + 3 + \frac{3}{{x}^{2}} - 9 = -6 + \frac{1}{x} + \frac{3}{x^{2}} \)
Factored
\[\frac{1}{x} + 3 + \frac{3}{{x}^{2}} - 9 = - \frac{6 x^{2} - x - 3}{x^{2}}\]