∂u/∂t + (u ⋅ ∇)u = -∇p + νΔu + f, ∇ ⋅ u = 0
u(x, 0) = u₀(x)
u(x,t) → 0 as |x| → ∞
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
∂u/∂t + (u ⋅ ∇)u = -∇p + νΔu + f, ∇ ⋅ u = 0
u(x, 0) = u₀(x)
u(x,t) → 0 as |x| → ∞
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.