r:
x = -1 + 2λ
y = -5 + 2λ
z = -3 + λ
s:
x = 7 + 4μ
y = μ
z = 1 + 2μ
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
r:
x = -1 + 2λ
y = -5 + 2λ
z = -3 + λ
s:
x = 7 + 4μ
y = μ
z = 1 + 2μ
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.