The Maclaurin series for f(x)=$3^{ $-x^{2}$ }$

asked by guest
on Nov 16, 2024 at 12:53 pm



You asked:

Find the Maclaurin series of the function f(x)=3−x2f\left( x \right) = {3}^{-{x}^{2}}.

MathBot Answer:

Series expansion:

1−x2log⁡(3)+x4log⁡(3)22−x6log⁡(3)36+x8log⁡(3)424−x10log⁡(3)5120+⋯1- x^{2} \log{\left(3 \right)} + \frac{x^{4} \log{\left(3 \right)}^{2}}{2}- \frac{x^{6} \log{\left(3 \right)}^{3}}{6} + \frac{x^{8} \log{\left(3 \right)}^{4}}{24}- \frac{x^{10} \log{\left(3 \right)}^{5}}{120}+ \cdots

+ Submit Question