The Maclaurin series for f(x)=$3^{ $-x^{2}$ }$

asked by guest
on Nov 16, 2024 at 12:53 pm



You asked:

Find the Maclaurin series of the function \(f\left( x \right) = {3}^{-{x}^{2}}\).

MathBot Answer:

Series expansion:

\[1- x^{2} \log{\left(3 \right)} + \frac{x^{4} \log{\left(3 \right)}^{2}}{2}- \frac{x^{6} \log{\left(3 \right)}^{3}}{6} + \frac{x^{8} \log{\left(3 \right)}^{4}}{24}- \frac{x^{10} \log{\left(3 \right)}^{5}}{120}+ \cdots\]

+ Submit Question