(4pq/(m-3))*((m^2-9)/8q^2)
You asked:
Evaluate the expression: \(\frac{4 p q}{m - 3} \cdot \frac{{m}^{2} - 9}{8 {q}^{2}}\)
MathBot Answer:
Evaluated
\(\displaystyle \frac{4 p q}{m - 3} \cdot \frac{{m}^{2} - 9}{8 {q}^{2}} = \frac{p \left(m^{2} - 9\right)}{2 q \left(m - 3\right)} \)
Expanded
\[\frac{4 p q}{m - 3} \cdot \frac{{m}^{2} - 9}{8 {q}^{2}} = \frac{4 m^{2} p q}{8 q^{2} m - 24 q^{2}} - \frac{36 p q}{8 q^{2} m - 24 q^{2}}\]
Factored
\[\frac{4 p q}{m - 3} \cdot \frac{{m}^{2} - 9}{8 {q}^{2}} = \frac{p \left(m + 3\right)}{2 q}\]