aₙ = 21 + (21/1²) + (21/2²) + (21/3²) + ... + (21/(n-1)²)lim(n→∞)

asked by guest
on Sep 23, 2024 at 1:14 am



Mathbot Says...

I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.


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