(255-b)*b
asked by guest on Mar 24, 2025 at 3:25 pm
You asked:
MathBot Answer:
(255−b)⋅b=b(255−b)\left(255 - b\right) \cdot b = b \left(255 - b\right)(255−b)⋅b=b(255−b)
(255−b)⋅b=−b2+255b\left(255 - b\right) \cdot b = - b^{2} + 255 b(255−b)⋅b=−b2+255b
(255−b)⋅b=−b(b−255)\left(255 - b\right) \cdot b = - b \left(b - 255\right)(255−b)⋅b=−b(b−255)
