find $$\int_{1}^{\2}1/x^2+6x+5x dx

asked by guest
on Nov 23, 2024 at 8:22 am



You asked:

Evaluate the integral: 121x2+6x+5xdx\int_{1}^{2}{\frac{1}{{x}^{2}} + 6 x + 5 x}dx

MathBot Answer:

Definite integral

121x2+6x+5xdx=17\int_{1}^{2}{\frac{1}{{x}^{2}} + 6 x + 5 x}dx = 17