find $$\int_{1}^{\2}1/x^2+6x+5x dx

asked by guest
on Nov 23, 2024 at 8:22 am



You asked:

Evaluate the integral: \(\int_{1}^{2}{\frac{1}{{x}^{2}} + 6 x + 5 x}dx\)

MathBot Answer:

Definite integral

\[\int_{1}^{2}{\frac{1}{{x}^{2}} + 6 x + 5 x}dx = 17\]