(-y-5)(-3y+1)(5y-1)=0
You asked:
Solve the equation \(\left(-y - 5\right) \cdot \left(-\left( 3 y \right) + 1\right) \cdot \left(5 y - 1\right) = 0\) for the variable \(y\).
MathBot Answer:
The 3 solutions to the equation are: \[\begin{aligned}y &= -5\\y &= \frac{1}{5} = 0.2\\y &= \frac{1}{3} = 0.\overline{3}\end{aligned}\]