ln(0.01) = ln(1-e^100t)

asked by guest
on Nov 18, 2024 at 9:36 pm



You asked:

Investigate the equation: \(\ln\left( 0.01 \right) = \ln\left( 1 - {e}^{100} \cdot t \right)\).

MathBot Answer:

The solution is: \[t = \frac{99}{100 e^{100}} \approx 3.6828752 \cdot 10^{-44}\]

\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).

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