xy+y^2=1 find second derivative
You asked:
Find the 2nd derivative of \(y\) with respect to \(x\), where \(x y + y^{2} = 1\).
MathBot Answer:
\[\frac{d^{2} y}{d x^{2}} = \frac{2 x y{\left(x \right)} + 2 y^{2}{\left(x \right)}}{x^{3} + 6 x^{2} y{\left(x \right)} + 12 x y^{2}{\left(x \right)} + 8 y^{3}{\left(x \right)}}\]