(100−5t)
−3
y=∫5(100−5t)
−3
dt=
2
1
(100−5t)
−2
+C
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
(100−5t)
−3
y=∫5(100−5t)
−3
dt=
2
1
(100−5t)
−2
+C
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.