\large\displaystyle\sum\limits_{k=0}^{{99}}{{{2(3)^{k}}}} \approx Choose 1 answer:

(Choice A)

5.15⋅10475.15 \cdot 10^{47}

A

5.15⋅10475.15 \cdot 10^{47}

(Choice B)

3.80⋅10303.80 \cdot 10^{30}

B

3.80⋅10303.80 \cdot 10^{30}

(Choice C)

2.37⋅10−302.37 \cdot 10^{-30}

C

2.37⋅10−302.37 \cdot 10^{-30}

(Choice D)

7.76⋅10−487.76 \cdot 10^{-48}

D

7.76⋅10−487.76 \cdot 10^{-48}

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asked by guest
on Mar 26, 2025 at 7:01 pm



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