x² + y² + 14x - 2y = -1
You asked:
Investigate the equation: \({x}^{2} + {y}^{2} + 14 x - 2 y = -1\).
MathBot Answer:
The graph of the equation \({x}^{2} + {y}^{2} + 14 x - 2 y = -1\) is a circle.
The coordinates of its center are \(\left(-7, 1\right)\).
Its radius is \(7\).
The cirlce has parameterization: \[\begin{aligned}x\left(\theta\right) &= -7 + 7 \cos{\left(\theta \right)}\\y\left(\theta\right) &= 1 + 7 \sin{\left(\theta \right)}\end{aligned}\]