sin((-11 π\piπ) /12)
asked by guest on Mar 28, 2025 at 4:36 pm
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MathBot Answer:
sin(−(11π)12)=−64+24≈−0.25881904510252076234889883762405\sin\left( \frac{-\left( 11 \pi \right)}{12} \right) = - \frac{\sqrt{6}}{4} + \frac{\sqrt{2}}{4} \approx -0.25881904510252076234889883762405sin(12−(11π))=−46+42≈−0.25881904510252076234889883762405
sin(−(11π)12)=sin(−⋅11⋅π⋅112)=sin(−1112⋅π)=−14⋅6+14⋅2\begin{aligned}\sin\left( \frac{-\left( 11 \pi \right)}{12} \right)&=\sin{\left(- \cdot 11 \cdot \pi \cdot \frac{1}{12} \right)}\\&=\sin{\left(- \frac{11}{12} \cdot \pi \right)}\\&=- \frac{1}{4} \cdot \sqrt{6} + \frac{1}{4} \cdot \sqrt{2}\end{aligned}sin(12−(11π))=sin(−⋅11⋅π⋅121)=sin(−1211⋅π)=−41⋅6+41⋅2
