2(y-1)+3(2y-2)+4-2y
asked by guest on Apr 07, 2025 at 4:17 am
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MathBot Answer:
2(y−1)+3(2y−2)+4−2y=6y−4\displaystyle 2 \left(y - 1\right) + 3 \left(2 y - 2\right) + 4 - 2 y = 6 y - 4 2(y−1)+3(2y−2)+4−2y=6y−4
2(y−1)+3(2y−2)+4−2y=6y−42 \left(y - 1\right) + 3 \left(2 y - 2\right) + 4 - 2 y = 6 y - 42(y−1)+3(2y−2)+4−2y=6y−4