y = x^{2} - x + 8
if the value of x=3
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
y = x^{2} - x + 8
if the value of x=3
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.