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(x^2+y^2)dx-(xy+x^2)dy=0
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on Nov 17, 2024 at 6:32 am
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Investigate the equation: \(\left({x}^{2} + {y}^{2}\right) \cdot d x - \left(x y + {x}^{2}\right) \cdot d y = 0\).
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