(t-2)(t+5)(t-4)
asked by guest on Feb 02, 2025 at 11:42 am
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MathBot Answer:
(t−2)(t+5)(t−4)=(t−4)(t−2)(t+5)\displaystyle \left(t - 2\right) \left(t + 5\right) \left(t - 4\right) = \left(t - 4\right) \left(t - 2\right) \left(t + 5\right) (t−2)(t+5)(t−4)=(t−4)(t−2)(t+5)
(t−2)(t+5)(t−4)=t3−t2−22t+40\left(t - 2\right) \left(t + 5\right) \left(t - 4\right) = t^{3} - t^{2} - 22 t + 40(t−2)(t+5)(t−4)=t3−t2−22t+40