(18*d+200)/9x = (18*d+200)/(9x+9) +1

d/x=(9*d+200)/9

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on Nov 24, 2024 at 8:18 am



You asked:

Solve the system of equations:18d+2009x=18d+2009x+9+1dx=9d+2009\begin{aligned}\frac{18 d + 200}{9 x} &= \frac{18 d + 200}{9 x + 9} + 1\\\frac{d}{x} &= \frac{9 d + 200}{9}\end{aligned}

MathBot Answer:

The system of equations has 22 solutions.

d=−39136+791i12+(12+791i6)22,x=12+791i6d = - \frac{391}{36} + \frac{\sqrt{791} i}{12} + \frac{\left(\frac{1}{2} + \frac{\sqrt{791} i}{6}\right)^{2}}{2}, x = \frac{1}{2} + \frac{\sqrt{791} i}{6}d=−39136+(12−791i6)22−791i12,x=12−791i6d = - \frac{391}{36} + \frac{\left(\frac{1}{2} - \frac{\sqrt{791} i}{6}\right)^{2}}{2} - \frac{\sqrt{791} i}{12}, x = \frac{1}{2} - \frac{\sqrt{791} i}{6}

ii is the imaginary unit, defined as i2=−1i^2 = -1.
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