(128 + $\sqrt{\2}$)/( $\sqrt{\2}$ + 1)
You asked:
Evaluate the expression: \(\frac{128 + \sqrt{2}}{\sqrt{2} + 1}\)
MathBot Answer:
\[\frac{128 + \sqrt{2}}{\sqrt{2} + 1} = \frac{\sqrt{2} + 128}{1 + \sqrt{2}} \approx 53.60512242138307119781446797463166\]
\[\begin{aligned}\frac{128 + \sqrt{2}}{\sqrt{2} + 1}& = \left(128 + \sqrt{2}\right) \cdot \frac{1}{\sqrt{2} + 1}\\& = \left(128 + \sqrt{2}\right) \cdot \frac{1}{1 + \sqrt{2}}\\& = \frac{1}{1 + \sqrt{2}} \cdot \left(128 + \sqrt{2}\right)\end{aligned}\]
asked 2 days ago
active 2 days ago