log2(m) + log4(3)=1/log3(2)
You asked:
Solve the equation \(\log_{2}\left( m \right) + \log_{4}\left( 3 \right) = \frac{1}{\log_{3}\left( 2 \right)}\) for the variable \(m\).
MathBot Answer:
The solution is: \[m = e^{\left(\frac{\log{\left(3 \right)}}{\log{\left(2 \right)}} - \frac{\log{\left(3 \right)}}{\log{\left(4 \right)}}\right) \log{\left(2 \right)}} \approx 1.7320508\]
\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).