sec 40° - √3 cosec ( 2×40°) = 4

asked by guest
on Nov 19, 2024 at 11:18 pm



You asked:

Investigate the equation: \(\sec\left( 40^{\circ} \right) - \sqrt{3} \cdot \csc\left( 2 \cdot 40^{\circ} \right) = 4\).

MathBot Answer:

This equation has no unknown quantities, so it is either true or false.

This equation is false because the left-hand side is not equal to the right-hand side.

The left-hand side of the equation is:

\[\sec\left( 40^{\circ} \right) - \sqrt{3} \cdot \csc\left( 2 \cdot 40^{\circ} \right) = - \sqrt{3} \csc{\left(80 ^\circ \right)} + \sec{\left(40 ^\circ \right)}\]

The right-hand side of the equation is:

\[4\]