If 9^x=3^(x-1)/2^(x+1), find x.
You asked:
Solve the equation \({9}^{x} = \frac{{3}^{x - 1}}{{2}^{x + 1}}\) for the variable \(x\).
MathBot Answer:
The solution is: \[x = - \frac{\log{\left(6 \right)}}{- \log{\left(3 \right)} + \log{\left(18 \right)}} \approx -1.0\]