, ∀η ∈ Ν : 1·3+2·4+3·5+...+n(n+2)=(n(n+1)·(2n+7))/6
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
, ∀η ∈ Ν : 1·3+2·4+3·5+...+n(n+2)=(n(n+1)·(2n+7))/6
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.