10^{2r+1}=17

asked by guest
on Oct 22, 2024 at 1:37 pm



You asked:

Solve the equation \({10}^{2 r + 1} = 17\) for the variable \(r\).

MathBot Answer:

The solution is: \[r = - \frac{1}{2} + \frac{\log{\left(17 \right)}}{2 \log{\left(10 \right)}} \approx 0.11522446\]

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