Iam giving you an equation calculateVcos¢\g [vsin¢+(√2gh+v^2sin^2¢)]Vcos¢\g [vsin¢+(√2gh+v^2sin^2¢)]

here v= 289.4

¢=15 degree

g= 10

h= 0.68

calculate?

asked by guest
on Nov 26, 2024 at 3:35 am



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