x^1+2x^2=7

-2x^1+5x^2=4

-5x^1+6x^2=-3

asked by guest
on Nov 24, 2024 at 9:40 pm



You asked:

Solve the system of equations:\[\begin{aligned}{x}^{1} + 2 {x}^{2} &= 7\\-\left( 2 {x}^{1} \right) + 5 {x}^{2} &= 4\\-\left( 5 {x}^{1} \right) + 6 {x}^{2} &= -3\end{aligned}\]

MathBot Answer:

The system of equations has \(2\) solutions.

\[x = \frac{5}{12} - \frac{\sqrt{47} i}{12}\]\[x = \frac{5}{12} + \frac{\sqrt{47} i}{12}\]


\(i\) is the imaginary unit, defined as \(i^2 = -1\).