(7-2x)^2
asked by guest on Apr 07, 2025 at 4:09 am
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MathBot Answer:
(7−2x)2=(7−2x)2\displaystyle {\left( 7 - 2 x \right)}^{2} = \left(7 - 2 x\right)^{2} (7−2x)2=(7−2x)2
(7−2x)2=4x2−28x+49{\left( 7 - 2 x \right)}^{2} = 4 x^{2} - 28 x + 49(7−2x)2=4x2−28x+49
(7−2x)2=(2x−7)2{\left( 7 - 2 x \right)}^{2} = \left(2 x - 7\right)^{2}(7−2x)2=(2x−7)2