Find the antiderivative

∫(3−4x)16dx

asked by guest
on Mar 20, 2025 at 11:52 am



You asked:

Evaluate the integral: ∫∫(3−4x)⋅16dxdx\int{\int{\left(3 - 4 x\right) \cdot 16}dx}dx

MathBot Answer:

Antiderivative

∫∫(3−4x)⋅16dxdx=24x2−32x33+C\int{\int{\left(3 - 4 x\right) \cdot 16}dx}dx = 24 x^{2} - \frac{32 x^{3}}{3} + C

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