u^2-u^3-ua+u^2a/u+a
asked by guest on Apr 04, 2025 at 10:51 am
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MathBot Answer:
u2−u3−ua+u2au+a=a−u3+u2{u}^{2} - {u}^{3} - u a + \frac{{u}^{2} a}{u} + a = a - u^{3} + u^{2}u2−u3−ua+uu2a+a=a−u3+u2