given that x=6 and y=-4, 5(x)/3(y)+x

asked by guest
on Mar 23, 2025 at 1:55 am



You asked:

Given the following equations: x=6y=−4\begin{aligned}x &= 6\\ y &= -4\end{aligned} Evaluate 5x3y+x\frac{5 x}{3 y} + x.

MathBot Answer:

5x3y+x=72\frac{5 x}{3 y} + x = \frac{7}{2}

x+5x3y=5⋅63(−4)+6=−5⋅64⋅3+6=6−52=72\begin{aligned}x + \frac{5 x}{3 y}&=\frac{5 \cdot 6}{3 \left(-4\right)} + 6\\&=-\frac{5 \cdot 6}{4 \cdot 3} + 6\\&=6 - \frac{5}{2}\\&=\frac{7}{2}\end{aligned}


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