Math Problem Solver

\[ \frac{1}{6} + \frac{1}{18} + \frac{1}{36} = \frac{1}{4} = 0.25 \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{1}{6}\), \(\frac{1}{18}\), and \(\frac{1}{36}\) is \(36\). \[ \begin{aligned} \frac{1}{6} + \frac{1}{18} + \frac{1}{36} &= \frac{1 \cdot 6}{6 \cdot 6} + \frac{1 \cdot 2}{18 \cdot 2} + \frac{1 \cdot 1}{36 \cdot 1} \\ &= \frac{6 + 2 + 1}{36} \\ &= \frac{9}{36} \\&= \frac{1}{4} \end{aligned} \]