f left parenthesis r right parenthesis equals StartRoot r plus 5 EndRoot plus 1
f(x-5)=?
You asked:
Evaluate the function \(f\left( r \right) = \sqrt{r + 5} + 1\) where \(r = x - 5\).
MathBot Answer:
$$\begin{aligned}f\left( x - 5 \right)&=\sqrt{x} + 1\end{aligned}$$