(x+2)!−5(x+1)!−12x!=0

asked by guest
on Nov 24, 2024 at 8:42 am



You asked:

Solve the equation \(\left( x + 2 \right)! - 5 \cdot \left( x + 1 \right)! - 12 \cdot x! = 0\) for the variable \(x\).

+ Submit Question