(3⁻¹ + 4⁻¹ + 5⁻¹)⁰

asked by guest
on Nov 25, 2024 at 4:22 am



You asked:

Evaluate the expression: \({\left( {3}^{-1} + {4}^{-1} + {5}^{-1} \right)}^{0}\)

MathBot Answer:

\[{\left( {3}^{-1} + {4}^{-1} + {5}^{-1} \right)}^{0} = 1\]


\[\begin{aligned}{\left( {3}^{-1} + {4}^{-1} + {5}^{-1} \right)}^{0}& = \left(\frac{1}{3} + \frac{1}{4} + \frac{1}{5}\right)^{0}\\& = \left(\frac{7}{12} + \frac{1}{5}\right)^{0}\\& = \left(\frac{47}{60}\right)^{0}\\& = 1\end{aligned}\]