Math Problem Solver

\[ 6\frac{3}{8} + 7\frac{1}{4} = \frac{109}{8} = 13.625 \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{6}{1}\), \(\frac{3}{8}\), \(\frac{7}{1}\), and \(\frac{1}{4}\) is \(8\). \[ \begin{aligned} 6\frac{3}{8} + 7\frac{1}{4} &= \frac{6 \cdot 8}{1 \cdot 8} + \frac{3 \cdot 1}{8 \cdot 1} + \frac{7 \cdot 8}{1 \cdot 8} + \frac{1 \cdot 2}{4 \cdot 2} \\ &= \frac{48 + 3 + 56 + 2}{8} \\ &= \frac{109}{8} \end{aligned} \]